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Question: A spherical black body with a radius of \(12cm\) radiates \(450W\) power at \(50K\). If the radius w...

A spherical black body with a radius of 12cm12cm radiates 450W450W power at 50K50K. If the radius were halved and the temperature doubled, the power radiated in watts would be:
A) 225225
B) 450450
C) 900900
D) 18001800

Explanation

Solution

To find the answer for the given question, first we need to know the power formula and the body is in a spherical black body with a radius and power are given in the question. Note that the radius is halved and the temperature is doubled. We need to calculate the power radiated in watts.

Formula used:
The power formula of spherical black body is
P=AσT4P = A\sigma {T^4}
If the rr is the radius of the spherical body
Then,
AA is the area of the body
σ\sigma is the Stefan’s constant
TT is the temperature of the body

Complete step by step answer:
Power formula of spherical body to calculate power radiated
\Rightarrow P=AσT4P = A\sigma {T^4}
The area of the sphere A=4πr2A = 4\pi {r^2}
If we substitute the area formula in power formula we get,
\Rightarrow P=4πr2.σ.T4P = 4\pi {r^2}.\sigma .{T^4}
Where σ\sigma is constant
So, Pr2T4P \propto {r^2}{T^4}
If the power radiated P1P{}_1 when the radius of the spherical body is 12cm12cm
The value of the power 450W450W is given in the question,
Then the equation becomes,
\Rightarrow P=(4πσ)r2T4=450P = \left( {4\pi \sigma } \right){r^2}{T^4} = 450…………………(1)
In the question the radius is halved and the temperature is doubled
So,
\Rightarrow r=r2r' = \dfrac{r}{2} and T=2TT' = 2T
\Rightarrow P=(4πσ)(r2)2(2T)4 P' = \left( {4\pi \sigma } \right){\left( {\dfrac{r}{2}} \right)^2}{\left( {2T} \right)^4}
\therefore P=(4πσr2T4)2422P' = \left( {4\pi \sigma {r^2}{T^4}} \right)\dfrac{{{2^4}}}{{{2^2}}}
Substitute the equation 1 then we get,
\Rightarrow P=450×4P' = 450 \times 4
\therefore P=1800P' = 1800 WW
The power radiated watts is 1800W1800W.

Therefore the option (D) is correct.

Note: In the above equations, Stephen's constant is used because if the energy emitted increases rapidly with increase in temperature which is proportional to the temperature raised to the fourth power. The black body which is used for the lighting, heating and the thermal imaging etc. as well as testing and the measurement applications.