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Question: A spherical black body with a radius of \(12cm\) radiates \(450W\) power at \(500K\). If the radius ...

A spherical black body with a radius of 12cm12cm radiates 450W450W power at 500K500K. If the radius were made half and if the temperature is doubled, the power radiated in watts would be given as,
A.1800 B.225 C.450 D.900 \begin{aligned} & A.1800 \\\ & B.225 \\\ & C.450 \\\ & D.900 \\\ \end{aligned}

Explanation

Solution

The power radiated by the black body is found by taking the product of the area of the black body, Stefan’s constant and the fourth power of temperature. The area is given as the area of a sphere as the black body is given as a spherical one. Now the conditions of halving the radius and making the temperature doubled, should be applied in the same equation and compare it with the previous condition. These all will help you to solve this question.

Complete step by step answer:
First of all we have to find the power radiated by the spherical body at specific conditions. It is given by the equation,
Pold=AσT4{{P}_{old}}=A\sigma {{T}^{4}}
As the area of the sphere is given by the equation,
A=4πr2A=4\pi {{r}^{2}}
Where rr be the radius of the spherical body.
Substituting this in the equation of power radiated,
Pold=4πr2σT4{{P}_{old}}=4\pi {{r}^{2}}\sigma {{T}^{4}}
The power radiated at 500K500K, given in the question is,
Pold=450W{{P}_{old}}=450W
Now let us look at the second case. As it is mentioned that the the radius is made half, we can write that,
rr2r\to \dfrac{r}{2}
And also the temperature is made twice, therefore we can write that,
T2TT\to 2T
Let us substitute this in the equation of power,
Pold=4πr2σT4=450W{{P}_{old}}=4\pi {{r}^{2}}\sigma {{T}^{4}}=450W
Pnew=4π(r2)2σ(2T)4{{P}_{new}}=4\pi {{\left( \dfrac{r}{2} \right)}^{2}}\sigma {{\left( 2T \right)}^{4}}
This can be simplified by doing the calculations,
Pnew=16×4πr2σT44=4×4πr2σT4{{P}_{new}}=\dfrac{16\times 4\pi {{r}^{2}}\sigma {{T}^{4}}}{4}=4\times 4\pi {{r}^{2}}\sigma {{T}^{4}}
Therefore we can write that,
Pnew=4×Pold{{P}_{new}}=4\times {{P}_{old}}
As the value of power in the old condition is given as,
Pold=450W{{P}_{old}}=450W
Substituting this in the equation will give the answer,
Pnew=4×450=1800W{{P}_{new}}=4\times 450=1800W
Therefore the correct answer is given as option A.

Note:
Stefan-Boltzmann law is the law explaining the power radiated by a black body. It says that the total power emitted or radiated from a surface is proportional to the fourth power of its absolute temperature. This law is applicable only to blackbodies.