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Question

Physics Question on thermal properties of matter

A spherical black body with a radius of 12cm12\,cm radiates 450watt450\,watt power at 500K500\,K. If the radius were halved and the temperature doubled, the power radiated in watt would be :

A

450

B

1000

C

1800

D

225

Answer

1800

Explanation

Solution

Rate of power loss
rR2T4r \propto R^{2} T^{4}
r1r2=R12T14R22T24\frac{r_{1}}{r_{2}}=\frac{R_{1}^{2} T_{1}^{4}}{R_{2}^{2} T_{2}^{4}}
=4×116=4 \times \frac{1}{16}
450r2=14\frac{450}{r_{2}}=\frac{1}{4}
r2=1800r_{2}=1800 watt