Question
Question: A spherical ball contracts in volume by 0.01 % when subjected to a normal uniform pressure of 100 at...
A spherical ball contracts in volume by 0.01 % when subjected to a normal uniform pressure of 100 atm. The Bulk modulus of its material is
(A). 1.01×1011Nm−2
(B). 1.01×1012Nm−2
(C). 1.01×1010Nm−2
(D). 1.01×1013Nm−2
Solution
Hint: Bulk modulus is a numerical constant that defines solid or fluid elastic properties when it is under pressure on all surfaces. The pressure applied increases the volume of a substance and when the pressure is removed returns to its original volume.
Formula used: B = (v△v)△PWhere,
B = Bulk modulus
△P = Change of the pressure or force applied on the material per unit area
△V= Change of material volume due to compression
V = Initial material volume in English system units, and N/m2in metric scale.
Complete step-by-step solution -
Since the number of spherical contracts is 0.01%
⇒v△v=1000.01
So Bulk modulus ‘B’ is given by
B = (v△v)△P
⇒B = 1000.01100×1.01×105
∵1 atm = 1.01 × 105N/m2
⇒B=1.01×1011Nm−2
Hence option A is the correct answer.
Additional information-
Bulk modulus is used to calculate the incompressibility of a solid. Besides, the higher value of K for a substance, the more incompressible its existence is. For example, for steel, the value of K is 1.6×1011N/m2and the value of K for glass is 4×1010N/m2. K for steel, here, is more than three times the glass value of K. Which means more compressible glass than steel.
The standard atmosphere (symbol: atm) is a pressure unit specified as 101325 Pa (1.01325 bar). It is commonly used as a reference or standard pressure. At sea level, it is nearly equal to the air pressure.
Note: Bulk elasticity modulus is the one measure of solids' mechanical properties. Certain elastic modules include module Young and module Shear. In any case, a material's bulk elastic properties are used to determine how much it can compress under a specified amount of outer pressure. Here the ratio of the change in pressure to the compression of the fractional volume is important to find and remember.