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Question: A spherical ball contracts in volume by \(0.01\% \) when subjected to a normal uniform pressure of \...

A spherical ball contracts in volume by 0.01%0.01\% when subjected to a normal uniform pressure of 100100 atmospheres. The bulk modulus of its material in dyne per centimeter square is:
A. 10×101110 \times {10^{11}}
B. 100×102100 \times {10^2}
C. 1×10111 \times {10^{11}}
D. 2×10112 \times {10^{11}}

Explanation

Solution

In this question pressure is given in atmospheric unit so try to change it in Newton per meter square by multiplying it with 1.01×1051.01 \times {10^5} and also to get the bulk modulus in dyne per centimeter square, multiply the resulting bulk modulus value by ten.

Formula used:
B=PΔvvB = \dfrac{P}{{\dfrac{{\Delta v}}{v}}} where BB is bulk modulus, PP is pressure exerted on the material, Δv\Delta v is change in volume of the object due to pressure and vv is the volume of the object.

Complete answer:
Given that,
Pressure exerted =100 = 100 atmospheres =100×1.01×105 = 100 \times 1.01 \times {10^5} Newton per meter square
And the spherical ball contracts in volume =0.01%= 0.01\%
Δvv=0.01100\therefore \dfrac{{\Delta v}}{v} = \dfrac{{0.01}}{{100}}
As we know that bulk modulus, B=PΔvvB = \dfrac{P}{{\dfrac{{\Delta v}}{v}}}, putting the values we get:
B=100×1.01×1050.01100B = \dfrac{{100 \times 1.01 \times {{10}^5}}}{{\dfrac{{0.01}}{{100}}}}
B=1.01×1011B = 1.01 \times {10^{11}}Newton per meter square
Therefore bulk modulus of material in dyne per centimeter square =1.01×1011×10=10.1×1011 = 1.01 \times {10^{11}} \times 10 = 10.1 \times {10^{11}}.

So, the correct answer is “Option A”.

Note:
Basically the bulk modulus of a substance is the measure of how resistant to compression a substance is and is given by the formula B=PΔvvB = \dfrac{P}{{\dfrac{{\Delta v}}{v}}} here we substituted the given mathematical values after conversion of units and got the value of bulk modulus as 10.1×101110.1 \times {10^{11}} dynes per centimeter square.