Question

A sphere rolls down on an inclined plane of inclination θ. What is the acceleration as the sphere reaches bottom

• A. $\frac{5}{7}g\sin\theta$
• B. $\frac{3}{5}g\sin\theta$
• C. $\frac{2}{7}g\sin\theta$
• D. $\frac{2}{5}g\sin\theta$

Answer 1

Answer: (A)

$\frac{5}{7}g\sin\theta$

Answer 2

Acceleration (1) $= \frac{g\sin\theta}{1 + \frac{K^{2}}{R^{2}}} = \frac{g\sin\theta}{1 + \frac{2}{5}} = \frac{5}{7}g\sin\theta$.