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Question

Physics Question on System of Particles & Rotational Motion

A sphere of diameter 0.2m0.2\, m and mass 2kg2\, kg is rolling on an inclined plane with velocity v=0.5m/s. v=0\, . 5\, m/s. The kinetic energy of the sphere is:

A

0.1 J

B

0.3 J

C

0.5 J

D

0.42 J

Answer

0.42 J

Explanation

Solution

The kinetic energy of sphere while rolling on an inclined plane is given by EKE_{ K } =Translational kinetic energy + Rotational kinetic energy =12mv2+12Iω2= \frac{1}{2} m v^{2}+\frac{1}{2} I \omega^{2} EK=12×2×(0.5)2+12×23×2×E_{K}=\frac{1}{2} \times 2 \times(0.5)^{2}+\frac{1}{2} \times \frac{2}{3} \times 2 \times (0.1)2×(0.50.1)2(0.1)^{2} \times\left(\frac{0.5}{0.1}\right)^{2} =0.25+0.17=0.42J=0.25+0.17=0.42\, J