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Question: A sphere, a cube and a thin circular plate, all made of same substance and all have same mass. These...

A sphere, a cube and a thin circular plate, all made of same substance and all have same mass. These are heated to 2000C and then placed in a room, then the

A

Temperature of sphere drops to room temperature at last

B

Temperature of cube drops to room temperature at last

C

Temperature of thin circular plate drops to room temperature at last

D

Temperature of all the three drops to room temperature at the same time

Answer

Temperature of sphere drops to room temperature at last

Explanation

Solution

dTdt=eAσmc(T4T04)=eAσVρc(T4T04)\frac{dT}{dt} = \frac{eA\sigma}{mc}(T^{4} - T_{0}^{4}) = \frac{eA\sigma}{V\rho c}(T^{4} - T_{0}^{4})

∴ Rate of cooling RAR \propto A

[As masses are equal then volume of each body must be equal because materiel is same]

i.e. rate of cooling depends on the area of cross-section and we know that for a given volume the area of cross-section will be minimum for sphere. It means the rate of cooling will be minimum in case of sphere.

So the temperature of sphere drops to room temperature at last.