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Question: A speaks the truth in 60% cases and B speaks the truth in 75% cases. The probability that they will ...

A speaks the truth in 60% cases and B speaks the truth in 75% cases. The probability that they will contradict each other in describing a single event is

A

11/20

B

9/20

C

13/20

D

7/20

Answer

9/20

Explanation

Solution

Required probability = P(1) P() + P( A\overline { \mathrm { A } } ) P(2)

= 35×14+25×34=920\frac { 3 } { 5 } \times \frac { 1 } { 4 } + \frac { 2 } { 5 } \times \frac { 3 } { 4 } = \frac { 9 } { 20 }