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Question

Physics Question on Gravitation

A space station is set up in space at a distance equal to earth's radius from earth's surface. Suppose a satellite can be launched from space station. Let V1V_1 and V2V_2 be the escape velocites of the satlhte on earth's surface and space station respectively. Then

A

V2=V1V_2=V_1

B

V2V_2

C

V2>V1V_2>V_1

D

No relation

Answer

V2V_2

Explanation

Solution

For an object to escape from an orbit, its total energy must be zero. For space station: T.E=12mv22+(GMm2R)=0T . E =\frac{1}{2} mv _{2}^{2}+\left(-\frac{ GMm }{2 R }\right)=0 v2=GMR\Longrightarrow v_{2}=\sqrt{\frac{G M}{R}} where RR is the radius of earth. For earth's surface : v1=2GMRv_{1}=\sqrt{\frac{2 GM }{ R }} Hence v1>v2v_{1}>v_{2}