Question
Physics Question on doppler effect
A source of sound S emitting waves of frequency 100Hz and an observor O are located at some distance from each other. The source is moving with a speed of 19.4ms−1 at an angle of 60∘ with the source observer line as shown in the figure. The observor is at rest. The apparent frequency observed by the observer is (velocity of sound in air 330ms−1 )
A
103 Hz
B
106 Hz
C
97 Hz
D
100 Hz
Answer
103 Hz
Explanation
Solution
Here, original frequency of sound, f0=100Hz Speed of source Vs19.4cos60∘=9.7 From Doppler's formula f1=f0(V−VsV−V0) f1=100(V−(+9.7)V−0) f1100V(1−V9.7)V f1=100(1+3309.7)=103Hz Apparent frequency f1=103Hz