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Question: A source of sound of frequency 450 cycles/sec is moving towards a stationary observer with 34 m/sec ...

A source of sound of frequency 450 cycles/sec is moving towards a stationary observer with 34 m/sec speed. If the speed of sound is 340 m/sec, then the apparent frequency will be

A

410 cycles/sec

B

500 cycles/sec

C

550 cycles/sec

D

450 cycles/sec

Answer

500 cycles/sec

Explanation

Solution

n=n(vvv0)=450(34034034)=500cycles/secn' = n\left( \frac{v}{v - v_{0}} \right) = 450\left( \frac{340}{340 - 34} \right) = 500cycles/\sec