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Question

Physics Question on Waves

A source of frequency 240Hz240\, Hz is moving towards an observer with a velocity of 20m/s20\, m/s. The observer is now moving away from the source with a velocity of 20m/s20\, m/s. Apparent frequency heard by observer, if velocity of sound is 340m/s340\, m/s, is

A

268 Hz

B

270 Hz

C

360 Hz

D

240 Hz.

Answer

240 Hz.

Explanation

Solution

The frequency of the source v0=240Hzv_{0}=240 \,Hz The velocity of the source us=+20m/su _{ s }=+20\, m / s (as it moves towards the observer) The velocity of the observer u0=20m/su _{0}=-20 \,m / s (as it moves away from the source) Applying Doppler's effect v=v0[v+u0vus]v=v_{0}\left[\frac{v+u_{0}}{v-u_{s}}\right] =240×[340+(20)34020]=240Hz=240 \times\left[\frac{340+(-20)}{340-20}\right]=240\, Hz