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Question: A sound wave travels with a velocity of 300 m s–1 through a gas. 9 beats are produced in 3 s when tw...

A sound wave travels with a velocity of 300 m s–1 through a gas. 9 beats are produced in 3 s when two waves pass through hit simultaneously. If one of the waves has 2 m wavelength, the wavelength of the other wave is

A

1.98 m

B

2.04 m

C

2.06 m

D

1.99 m

Answer

2.04 m

Explanation

Solution

No, of beats per seconds = 93=3s1\frac{9}{3} = 3s^{- 1}

No, of beats per seconds =υ1υ2= \upsilon_{1} - \upsilon_{2}

3=vλ1vλ2=v[1λ11λ2]3 = \frac{v}{\lambda_{1}} - \frac{v}{\lambda_{2}} = v\left\lbrack \frac{1}{\lambda_{1}} - \frac{1}{\lambda_{2}} \right\rbrack

3300=121λ2\frac{3}{300} = \frac{1}{2} - \frac{1}{\lambda_{2}}

1λ2=121100=501100=49100\frac{1}{\lambda_{2}} = \frac{1}{2} - \frac{1}{100} = \frac{50 - 1}{100} = \frac{49}{100}

λ2=10049=2.04m\lambda_{2} = \frac{100}{49} = 2.04m