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Question: A sound wave of frequency 500 Hz covers a distance of 1000 m in 5 second between points X and Y. The...

A sound wave of frequency 500 Hz covers a distance of 1000 m in 5 second between points X and Y. The number of waves between X and Y are –

A

500

B

1000

C

2500

D

5000

Answer

500

Explanation

Solution

v =(γP/ρ)\sqrt{(\gamma P/\rho)}, the density r of moisture is less than the density of air. Hence, the presence of moisture in air lowers the density. So, the velocity of sound in air increases.