Question

A solution wiht $pH = 2$ is more acidic than one with a $pH = 6$, by a factor

• A. 4000
• B. 5000
• C. 8000
• D. 10000

Answer 1

Answer: (D)

10000

Answer 2

$pH = -log \left[H^{+}\right]$ $\Rightarrow 2 = -log \left[H ^{+}\right]_{1},$ and $6 = - log \left[H^{+} \right]_{2}$ $\Rightarrow \frac{log\left[H^{+}\right]_{1}}{log\left[H^{+}\right]_{2}}=\frac{10^{-2}}{10^{-6}}=10^{4}=10,000$ Therefore, acidity is more in pH=2 than pH=6 by an order of 10,000.