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Question: A solution of urea (mol. mass 56g mol<sup>–1</sup>) boils at 100.18°C at the atmospheric pressure. I...

A solution of urea (mol. mass 56g mol–1) boils at 100.18°C at the atmospheric pressure. If KfK_{f} and KbK_{b}for water are 1.86 and 0.512K kg mol–1 respectively the above solution will freeze at.

A

– 6.54°C

B

6.54°C

C

0.654°C

D

–0.654°C

Answer

–0.654°C

Explanation

Solution

ΔTb=0.18\Delta T_{b} = 0.18; ΔTb=mKb\Delta T_{b} = mK_{b}

0.18ΔTf=mKbmKf\frac{0.18}{\Delta T_{f}} = \frac{mK_{b}}{mK_{f}}; 0.18×1.860.512=ΔTf\frac{0.18 \times 1.86}{0.512} = \Delta T_{f} ; ΔTf=0.653\Delta T_{f} = 0.653

T0Ts=0.653T^{0} - T_{s} = 0.653;T0Ts=0.653T^{0} - T_{s} = 0.653; Ts=00.653oCT_{s} = 0 - 0.653^{o}C.