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Question: A solution of urea in water is 3000ppm by weight. if the density of this solution is 1.04 g/ ml. Wha...

A solution of urea in water is 3000ppm by weight. if the density of this solution is 1.04 g/ ml. What is the molar strength of the solution?

Explanation

Solution

Molarity is also known as molar strength and is defined as the number of moles of solute present in one litre of solution. Mathematically it is given as:
Molarity=no.of moles of solutevolume of solutionMolarity = \dfrac{{{\text{no}}{\text{.of moles of solute}}}}{{{\text{volume of solution}}}}

Complete step by step answer:
As we know ppm stands for parts per million. Mathematically it is represented as:
ppm=Mass of the componentmass of the solution×106ppm = \dfrac{{{\text{Mass of the component}}}}{{{\text{mass of the solution}}}} \times {10^6}
The density of a solution is related to mass and volume and the formula for density is given as:
Density=MassVolumeDensity = \dfrac{{Mass}}{{Volume}}
On putting the given value of density and volume we can calculate the mass of solution as:
1.04=Mass10001.04 = \dfrac{{Mass}}{{1000}}
1.04×1000=Mass of the solution\Rightarrow 1.04 \times 1000 = {\text{Mass of the solution}}
Mass of the solution = 1040g\Rightarrow {\text{Mass of the solution = }}1040g
As per the question, it is given that solution of urea in water is 3000ppm by weight, then the mass of the urea is calculated as:
3000=Mass of the component140×1063000 = \dfrac{{{\text{Mass of the component}}}}{{140}} \times {10^6}
3000×1040106=Mass of the component\Rightarrow \dfrac{{3000 \times 1040}}{{{{10}^6}}} = {\text{Mass of the component}}
Mass of the component = 3.12g\Rightarrow {\text{Mass of the component = 3}}{\text{.12g}}
Since the molar strength (molarity) is given as:
Molarity=no.of moles of solutevolume of solutionMolarity = \dfrac{{{\text{no}}{\text{.of moles of solute}}}}{{{\text{volume of solution}}}}
Number of moles of solute (urea) = given mass/ molecular mass
Number of moles of urea = 3.1260\dfrac{{3.12}}{{60}}
And the volume of the solution is 1 litre, then the Molarity is calculated as:
Molarity=3.1260×1Molarity = \dfrac{{3.12}}{{60 \times 1}}
Hence, the Molar strength of the solution is 0.052M

Additional Information:
Apart from Molarity, we have other concepts also that relate to the concentration of a solute in a solvent. They are:
Molality: It is defined as the number of moles of solute in one kg of solution.
Weight percent: It is defined as the ratio of the mass of solute to the mass of solution multiplied by 100 is represented as w/w %. It is also known as Mass per Cent.

Note: We use molar concentration instead of molecular concentration as the number of molecules in a solution will be high as per the definition of a mole; it is equal to the gram-equivalent weight of the Avogadro's number of molecules, i.e. 6.023×10236.023 \times {10^{23}}. So it will be simpler to represent the concentration in terms of moles per litre.