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Question

Chemistry Question on Colligative Properties

A solution of sucrose (Molar mass = 342g/mol342\,g/mol) is prepared by dissolving 68.4g68.4\, g of it per litre of solution, what is its osmotic pressure (R=0.082LR = 0.082 \,L atom K1K^{-1} mol1mol^{-1}) at 273K273\, K?

A

3.92 atm

B

4.48 atm

C

5.92 atm

D

29.4 atm

Answer

4.48 atm

Explanation

Solution

Osmotic pressure (π)=CRT(\pi)= CRT Here, C=C = concentration of solution C=nVC =\frac{ n }{ V } n=wm= weight in gram of substance  Mol. weight of substance \therefore n =\frac{ w }{ m }=\frac{\text { weight in gram of substance }}{\text { Mol. weight of substance }} V=1V =1 litre C=68.4342C =\frac{68.4}{342} π=68.4342×0.082×273\pi=\frac{68.4}{342} \times 0.082 \times 273 =4.48atm=4.48\, atm