Question

A solution of ${Ni(NO3)2}$ is electrolysed between platinum electrodes using $0.1$ Faraday electricity. How many mole of $Ni$ will be deposited at the cathode?

• A. 0.2
• B. 0.05
• C. 0.1
• D. 0.15

Answer 1

Answer: (B)

0.05

Answer 2

0.1 e of $Ni^{+2}$ will be discharged.
No. of eq = (No of moles) $\times$ (n-factor)
0.1 = (No. of moles) $\times$ 2
No. of moles of Ni = $\frac{0.1}{2} = 0.05$