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Chemistry Question on Acids and Bases

A solution of an acid has [H+]=2×10−5\left[ H ^{+}\right]=2 \times 10^{-5}. Find out the concentration of OH−OH ^{-}ions.

A

5×10−10N5 \times 10^{-10} N

B

4×10−10N4 \times 10^{-10} N

C

2×10−5N2 \times 10^{-5} N

D

9×10−4N9 \times 10^{-4} N

Answer

5×10−10N5 \times 10^{-10} N

Explanation

Solution

[H]+[OH−]=Kw[H]^{+}\left[O H^{-}\right]=K_{w} 2×10−5×[OH−]=1×10−142 \times 10^{-5} \times\left[O H^{-}\right]=1 \times 10^{-14} [OH−]=1×10−142×10−5[O H^-]=\frac{1 \times 10^{-14}}{2 \times 10^{-5}} =0.5×10−9=0.5 \times 10^{-9} =5×10−10=5 \times 10^{-10}