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Question: A solution of 500 ml of 0.2 M KOH and 500 ml of 0.2M HCl is mixed and stirred, the rise in temperatu...

A solution of 500 ml of 0.2 M KOH and 500 ml of 0.2M HCl is mixed and stirred, the rise in temperature is T1{{T}_{1}}. The experiment is repeated using 250 ml each of solution, the temperature rise is T2{{T}_{2}}, which of the following is true?
A) T1=T2{{T}_{1}} = {{T}_{2}}
B) T1=2T2{{T}_{1}} = 2{{T}_{2}}
C) T1=4T2{{T}_{1}} = 4{{T}_{2}}
D) T2=9T1{{T}_{2}} = 9{{T}_{1}}

Explanation

Solution

. The temperature difference can be calculated using the equation, Q=mCVΔTQ = m{{C}_{V}}\Delta T
- Where Q is the heat and n is the number of moles, CV{{C}_{V}} is the specific heat capacity of a substance and ΔT\Delta T is the change in temperature.

Complete step by step answer:
In the question, it is given than a solution of 500 ml of 0.2 M KOH and 500 ml of 0.2 M HCl is mixed and the temperature during the reaction is noted as T1{{T}_{1}} and then another reaction is carried out by mixing 250 ml of KOH and 250 ml of HCl solution of 0.2 M and change in temperature can be calculated ieT2{{T}_{2}}.
The reaction involved here is,
KOH+HClKCl+H2OKOH+HCl\to KCl+{{H}_{2}}O
For finding the moles we can use the equation,
No. of moles =Molarity of the solution ×\times Volume of the solution
Here the molarity of the solution is taken as 0.2 M as both the solutions have the same molarity and the volume of the solution is 500 ml.
No. of moles = 0.2 ×\times 500 = 100
As in the question, CV{{C}_{V}} is not given we eliminate the term and rewrite the equation as, Q=nΔTQ=n\Delta T
For Q1{{Q}_{1}}, Q1=nΔT=100×T1=100T1{{Q}_{1}} = n\Delta T = 100\times {{T}_{1}} = 100{{T}_{1}}
Molarity of the solution is 0.2M and the volume of the solution is 250ml.
No. of moles = 0.2×\times250 = 50
ForQ2{{Q}_{2}},Q2=nΔT=50×T2=50T2{{Q}_{2}} = n\Delta T= 50\times {{T}_{2}} = 50{{T}_{2}}
From the equations obtained we can say that the Q1=2Q2{{Q}_{1}} = 2{{Q}_{2}}
Q1=2Q2{{Q}_{1}} = 2{{Q}_{2}}
100T1=2×50T2100{{T}_{1}} = 2\times 50{{T}_{2}}
100T1=100T2100{{T}_{1}} = 100{{T}_{2}}
T1=T2{{T}_{1}} = {{T}_{2}}
So, the correct answer is “Option A”.

Note: If mass is given in the question, then we can alter the equation as,Q=mCVΔTQ = m{{C}_{V}}\Delta T
Where m is the mass of the substance given in the question.
- And for such problems the value for specific heat capacity of the substance CV{{C}_{V}}, will be provided in the question.