Question
Question: A solution of 500 ml of 0.2 M KOH and 500 ml of 0.2M HCl is mixed and stirred, the rise in temperatu...
A solution of 500 ml of 0.2 M KOH and 500 ml of 0.2M HCl is mixed and stirred, the rise in temperature is T1. The experiment is repeated using 250 ml each of solution, the temperature rise is T2, which of the following is true?
A) T1=T2
B) T1=2T2
C) T1=4T2
D) T2=9T1
Solution
. The temperature difference can be calculated using the equation, Q=mCVΔT
- Where Q is the heat and n is the number of moles, CV is the specific heat capacity of a substance and ΔT is the change in temperature.
Complete step by step answer:
In the question, it is given than a solution of 500 ml of 0.2 M KOH and 500 ml of 0.2 M HCl is mixed and the temperature during the reaction is noted as T1 and then another reaction is carried out by mixing 250 ml of KOH and 250 ml of HCl solution of 0.2 M and change in temperature can be calculated ieT2.
The reaction involved here is,
KOH+HCl→KCl+H2O
For finding the moles we can use the equation,
No. of moles =Molarity of the solution × Volume of the solution
Here the molarity of the solution is taken as 0.2 M as both the solutions have the same molarity and the volume of the solution is 500 ml.
No. of moles = 0.2 × 500 = 100
As in the question, CV is not given we eliminate the term and rewrite the equation as, Q=nΔT
For Q1, Q1=nΔT=100×T1=100T1
Molarity of the solution is 0.2M and the volume of the solution is 250ml.
No. of moles = 0.2×250 = 50
ForQ2,Q2=nΔT=50×T2=50T2
From the equations obtained we can say that the Q1=2Q2
Q1=2Q2
100T1=2×50T2
100T1=100T2
T1=T2
So, the correct answer is “Option A”.
Note: If mass is given in the question, then we can alter the equation as,Q=mCVΔT
Where m is the mass of the substance given in the question.
- And for such problems the value for specific heat capacity of the substance CV, will be provided in the question.