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Question: A solution is prepared by mixing equal volumes of 0.4 M CH<sub>3</sub>COOH and 0.2 M CH<sub>3</sub>C...

A solution is prepared by mixing equal volumes of 0.4 M CH3COOH and 0.2 M CH3COONa. Ka for CH3COOH = 10–6. The pH of the resulting solution would be –

A

6

B

5.69

C

6.69

D

6.5

Answer

5.69

Explanation

Solution

pH = pKa + log [ Salt ][ Acid] \frac { [ \text { Salt } ] } { [ \text { Acid] } }