Question

A solution is prepared by dissolving $0.6\, g$ of urea (molar mass = $60\, g\, mol^{-1})$ and $1.8\, g$ of glucose (molar mass = $180\, g$ mol${-1}$) in $100\, mL$ of water at $27^{\circ}C$. The osmotic pressure of the solution is : $(R = 0.08206 \; L \; atm \; K^{-1} \; mol^{-1} )$

• A. 4.92 atm
• B. 1.64 atm
• C. 2.46 atm
• D. 8.2 atm

Answer 1

Answer: (A)

4.92 atm

Answer 2

$\Pi = \frac{\left(\frac{0.6}{60} + \frac{1.8}{180}\right)}{0.1} \times0.08206 \times30$
$\Pi =4.9236\, \text{atm}$