Question

A solution is prepared by adding 1 mole ethyl alcohol in 9 mole water. The mass percent of solute in the solution is ___________ (Integer Answer)
(Given : Molar mass in g mol$^{-1}$ Ethyl alcohol : 46, water : 18)

Answer 1

Step 1: Calculate the mass of ethyl alcohol and water
$\text{Mass of ethyl alcohol} = 1 \, \text{mole} \times 46 \, \text{g mol}^{-1} = 46 \, \text{g}.$
$\text{Mass of water} = 9 \, \text{mole} \times 18 \, \text{g mol}^{-1} = 162 \, \text{g}.$
Step 2: Calculate total mass of solution
$\text{Total mass of solution} = \text{Mass of ethyl alcohol} + \text{Mass of water} = 46 + 162 = 208 \, \text{g}.$
Step 3: Calculate mass percent of ethyl alcohol
$\text{Mass percent of ethyl alcohol} = \frac{\text{Mass of ethyl alcohol}}{\text{Total mass of solution}} \times 100.$
$\text{Mass percent} = \frac{46}{208} \times 100 = 22.11\%.$
Final Answer: 22