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Question: A solution has a \[pH\] = 10. What is the \[\left[ {O{H^ - }} \right]\]? A.\[1 \times {10^{ - 4}}\...

A solution has a pHpH = 10. What is the [OH]\left[ {O{H^ - }} \right]?
A.1×1041 \times {10^{ - 4}}M
B.1×10101 \times {10^{ - 10}}M
C.1×1021 \times {10^{ - 2}}M
D.1×1061 \times {10^{ - 6}}M

Explanation

Solution

To calculate the [OH]\left[ {O{H^ - }} \right] of a solution we need to know the   pOH\;pOH . The   pOH\;pOH can be calculated using the expression:
pH + pOH = 14pH{\text{ }} + {\text{ }}pOH{\text{ }} = {\text{ }}14
Then [OH]\left[ {O{H^ - }} \right] can be calculated by using:
pOH =   log[OH]pOH{\text{ }} = \;{\text{ }} - {\text{log}}[O{H^ - }]

Complete step by step answer:
In aqueous solution, an acid is a substance which increases the concentration of [H+][{H^ + }] and a base increases the concentration of [OH][O{H^ - }]. The concentration of these ions varies over a wide range.
So to avoid dealing with such a wide range of ion concentration, scientists have converted these concentrations into pHpH and pOHpOH.
Where pHpH is negative log of [H+][{H^ + }] ions concentration and pOHpOH is negative log of [OH][O{H^ - }] ions concentration.
According to the given question
pHpH = 10
Therefore we know that, the sum of pHpH and pOHpOH is 14

\Rightarrow pH{\text{ }} + {\text{ }}pOH{\text{ }} = {\text{ }}14 \\\ \Rightarrow pOH = 4 \\\

Now [OH][O{H^ - }] can be calculated as follows,

pOH =   log[OH] [OH]=10pOH [OH]=104=1×104 pOH{\text{ }} = \;{\text{ }} - {\text{log}}[O{H^ - }] \\\ \Rightarrow [O{H^ - }] = {10^{ - pOH}} \\\ \Rightarrow [O{H^ - }] = {10^{ - 4}} = 1 \times {10^{ - 4}} \\\

Therefore, the [OH]\left[ {O{H^ - }} \right] ion concentration in the given solution is 1×1041 \times {10^{ - 4}} M
Thus, option A is the correct answer.

Additional Information:
Converting [H+][{H^ + }] to pHpH, is a convenient way to relate the acidity or basicity of a solution. The pHpH scale allows us to differentiate substances easily by their pHpH value.
The pHpH scale is a negative log scale of concentration of [H+][{H^ + }]. The log part indicates that thepHpH changes by 1 unit for every power of 10 change in concentration of [H+][{H^ + }]. The negative sign with log tells that pHpH and [H+][{H^ + }] are inversely related. When pHpH Increases [H+][{H^ + }] decreases, and when pHpH decreases [H+][{H^ + }] increases.

Note:
For aqueous solutions at 25C25^\circ C:
pHpH= 7, It is called a Neutral solution.
pHpH< 7, It is called an Acidic solution.
pHpH> 7, It is called a Basic solution.
The lesser the pHpH value, more acidic the solution will be and higher the pHpH value, more basic the solution will be.