Question
Question: A solution contains 36% water and 64% acetaldehyde \(\left( {C{H_3}CHO} \right)\) by mass. The mole ...
A solution contains 36% water and 64% acetaldehyde (CH3CHO) by mass. The mole fraction of acetaldehyde is:
A) 0.42
B) 0.2
C) 4.2
D) 2.1
Solution
Mole fraction is a method of expressing the concentration of the components of a mixture or a solution calculated using the value of moles of each component present in the mixture or solution
Its value is independent of the temperature hence is widely used as a concentration expressing unit in solutions and mixtures.
Formula used:
Xa=na+nbna
Xb=na+nbnb
Where Xa is the mole fraction of component ‘a’ present in the mixture of ‘a’ and ‘b’
Xb Is the mole fraction of component ‘b’ present in the mixture of ‘a’ and ‘b’
While naandnb are the moles of component ‘a’ and component ‘b’
Xa+Xb=1 (Always)
Complete step by step solution:
In the given question a solution of water and acetaldehyde is given
Let the weight of solution be 100gm
Then given water is 36% present in the solution hence it is 36gm
And acetaldehyde given as 64% would be 64gm
Now moles of a molecule is given by n=Molecularweightgivenweight
Using this moles of acetaldehyde (also known as ethanal) will be
na=4464
na=1.4545
And moles of water will be
nb=1836
nb=2
As we know mole fraction is calculated as
Xa=na+nbna
Using this mole fraction of acetaldehyde will be
Xa=1.4545+21.4545
Xa=0.42
Hence option “A” is the correct solution for this question.
Additional Information:
-Mole fraction of a particular component in a mixture of at least two components will always be lesser than one
-Pressure due to an individual gas in a mixture of gases commonly known as partial pressure is directly proportional to the mole fraction of that gas
Note:
-Mole fraction being a ratio of number of moles is dimensionless.
-Also, Mole fraction and Molality are the only two concentration expression units whose value remains constant whatever be the changes in the surrounding temperature.