Question
Question: A solution contains 25% water, 50% ethanoic acid, and 25% ethanol by mass. Compute the mole fraction...
A solution contains 25% water, 50% ethanoic acid, and 25% ethanol by mass. Compute the mole fraction of each.
Solution
Mole fraction of the component is calculated by dividing the mole of the component to the total moles of all the components in the solution. The moles of the component is calculated by dividing the given mass of the component to the molecular mass of it.
Complete answer:
Mole fraction of any component in the solution is equal to the number of moles of that component divided by the total number of moles of all the components. For a solution containing n2 moles of the solute dissolved in n1 moles of the solvent.
Mole fraction of solute = x2=n2+n1n2
Mole fraction of solvent = x1=n2+n1n1
The sum of the mole fraction of the components is equal to 1.
The moles of the component is calculated by dividing the given mass of the component to the molecular mass of it.
moles=molecular massgiven mass
So, in the question the solution contains 25% water, 50% ethanoic acid, and 25% ethanol by mass.
25% of water means 25 g of water is present in 100 g of solution.
50% of ethanoic acid means 50 g of ethanoic acid is present in 100 g of solution.
25% of ethanol means 25 g of ethanol is present in 100 g of solution.
The molecular mass of water = 18g/mol
The molecular mass of ethanoic acid = 60g/mol
The molecular mass of ethanol = 46g/mol
Number of moles of water = 1825=1.4
Number of moles of ethanoic acid = 6050=0.8
Number of moles of ethanol = 4625=0.54
So, the total number of moles of all components in the solution = 1.4+0.54+0.8 = 2.74
So, we have the moles of each component and total moles of the solution, therefore,
Mole fraction of water = 2.741.4=0.51
Mole fraction of ethanoic acid =2.740.8=0.291
Mole fraction of ethanol = 2.740.54=0.197
Hence the mole fraction of water is 0.51, ethanoic acid is 0.291, and ethanol is 0.197.
Note:
Mole fraction is a dimensionless quantity because we are dividing the moles with moles. When the percentage of the components is converted into mass, 100 g of the solution is taken for the easy calculation.