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Question: A solution contains 0.05 (M) each of NaCl and Na<sub>2</sub>CrO<sub>4</sub>. Solid AgNO<sub>3</sub> ...

A solution contains 0.05 (M) each of NaCl and Na2CrO4. Solid AgNO3 is gradually added to it. Ksp (AgCl) = 1.7 × 10–10 and Ksp (Ag2CrO4) =1.9 × 10–12

Which of the following would occur ?

A

Cl ions are precipitated first

B

CrO42– ions are precipitated first

C

Both Cl and CrO42– ions are precipitated together

D

The second ion starts precipitating when half of the first ion is precipitated

Answer

Cl ions are precipitated first

Explanation

Solution

To precipitate Cl, required [Ag+] = (Ksp)AgCl0.05\frac{(K_{sp})_{AgCl}}{0.05}

To precipitate CrO42– , required [Ag+] = {(Ksp)Ag2CrO40.05}1/2\left\{ \frac{(K_{sp})_{Ag_{2}CrO_{4}}}{0.05} \right\}^{1/2}

Since for the precipitation of Ag­2CrO4 required concentration of Ag+ is greater, hence Cl ions precipitate first in the form of AgCl (s).