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Question: A solution containing a large amount of \(A\) and water is steam distilled. The condensate hence obt...

A solution containing a large amount of AA and water is steam distilled. The condensate hence obtained contains 0.250.25 mole fraction of AA. The external pressure at which distillation is performed is (Pw=740{P_w} = 740).
A.760torr760torr
B.791.3torr791.3torr
C.986.67torr986.67torr
D.886.9torr886.9torr

Explanation

Solution

Raoult’s law: It states that partial vapour pressure of each component of an ideal mixture of liquids is equal to the product of vapour pressure of the pure substance with the mole fraction of that component in the mixture.

Complete step by step answer:
Let us first define mole fraction.
Mole fraction: It is defined as the ratio of number of moles of the solute or solvent to the total number of moles present in the solution.
If we want to calculate the mole fraction of solute then number of moles of solute is divided by the total number of moles in the solution and if we want to calculate the mole fraction of solvent then number of moles of solvent is divided by the total number of moles in the solution. And the sum of the mole fraction of solute and mole fraction of solvent is always equal to 11. As by the question we know that mole fraction if solute is given 0.250.25 then the mole fraction of the water in the solution will be 0.750.75.
Now we know the value of mole fraction of solute and mole fraction of solvent and also we know the vapour pressure of the solute and we have to find the vapour pressure of the solvent.
And the relation between these term are as follows:
PAPB=xAxB\dfrac{{{P_A}}}{{{P_B}}} = \dfrac{{{x_A}}}{{{x_B}}} where PA{P_A} is vapour pressure of solute AA, PB{P_B} is vapour pressure of solvent and xA{x_A} is the mole fraction of solute and xB{x_B} is the mole fraction of solvent.
In the question PB=740,xA=0.25,xB=0.75{P_B} = 740,{x_A} = 0.25,{x_B} = 0.75
PA=0.250.75×740 PA=7403  {P_A} = \dfrac{{0.25}}{{0.75}} \times 740 \\\ {P_A} = \dfrac{{740}}{3} \\\
So the external pressure will be PA+PB{P_A} + {P_B}. So external pressure is
740+7403=43×740=986.67torr740 + \dfrac{{740}}{3} = \dfrac{4}{3} \times 740 = 986.67torr.

So option C is correct.

Note:
Torr is used to measure the pressure. Pressure is defined as force per unit area. So its SI unit is N/m2N/{m^2} but its other units which are SI units are as Pascal represented by PaPa and 1Pa=1N/m21Pa = 1N/{m^2}. And one more unit is torr which is 1torr=133.32Pa1torr = 133.32Pa.