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Chemistry Question on Solutions

A solution containing 2 g2 \,g of a non-volatile solute in 20 g20 \,g of water boils at 373.52K373.52 K. The molecular mass of the solute is ______g mol−1g\, mol ^{-1} (Nearest integer).
Given, water boils at 373 K,Kb373\, K , K _{ b } for water =0.52 K kg mol−1=0.52 \,K\, kg \,mol ^{-1}

Answer

ΔTb​=373.52−373=0.52ΔT_b​=373.52−373 =0.52

ΔTb​=Kb⋅mΔT_b​=K_b⋅m

So, 0.52=0.52×2Molar mass×20×10−31​So,\,0.52= 0.52× \frac2{Molar \,mass} ×20×10^{−31​ }

Molar  mass=100g/molMolar \,\,mass =100g/mol.

Therefore, The correct answer is 100.\text{Therefore, The correct answer is 100.}