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Question

Chemistry Question on The solid state

A solid X+YX^{+} Y^{-} has a bee structure. If the distance of closest approach between the two atoms is 173 pm, the edge length of the cell is

A

200 pm

B

3/2pm\sqrt{3} / \sqrt{2} pm

C

142.2 pm

D

2pm\sqrt{2} pm

Answer

200 pm

Explanation

Solution

Nearest neighbour distance (d)=1.73?(d)=1.73 ? For bcc,d=32a(a=b c c, d=\frac{\sqrt{3}}{2} a(a= edge length )) a=1.73×23=2? or 200pma=\frac{1.73 \times 2}{\sqrt{3}}=2 ? \text { or } 200 \,pm