Question

A solid sphere rolls down an inclined plane and its velocity at the bottom is v₁. Then same sphere slides down the plane (without friction) and let its velocity at the bottom be v₂. Which of the following relation is correct

• A. v₁ = v₂
• B. $v_{1} = \frac{5}{7}v_{2}$
• C. $v_{1} = \frac{7}{5}v_{2}$
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

When solid sphere rolls down an inclined plane the velocity at bottom $v_{1} = \sqrt{\frac{10}{7}gh}$

but, if there is no friction then it slides on inclined plane and the velocity at bottom $v_{2} = \sqrt{2gh}$

$\therefore\frac{v_{1}}{v_{2}} = \sqrt{\frac{5}{7}}$.