Question

A solid sphere of radius R and M is placed on a smooth horizontal floor. If it given a horizontal impulse F at a height h above centre of mass and the sphere starts rolling, then its angular speed w is –

• A. w =$\frac{2F.h}{5R^{2}M}$
• B. w = $\frac{5}{2}$ × $\frac{Fh}{MR^{2}}$
• C. w = $\frac{F}{hM}$
• D. w =$\frac{7Fh}{5MR^{2}}$

Answer 1

Answer: (B)

w = $\frac{5}{2}$ × $\frac{Fh}{MR^{2}}$

Answer 2

Angular impulse = Change in angular momentum

\ F × h = $\frac{2}{5}$ MR² × w

\ w = $\frac{5}{2}$ × $\frac{Fh}{MR^{2}}$