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Question

Physics Question on System of Particles & Rotational Motion

A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity vm/sv\, m/s. If it is to climb the inclined surface then vv should be

A

107gh\geq \sqrt{\frac{10}{7} g h}

B

2gh\ge\sqrt{2gh}

C

2gh2gh

D

107gh\frac{10}{7} g h

Answer

107gh\geq \sqrt{\frac{10}{7} g h}

Explanation

Solution

Kinetic energy is converted to potential energy. From law of conservation of energy, energy can neither be created nor destroyed but it remains conserved. In the given case the sum of kinetic energy of rotation and translation is converted to potential energy.