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Question

Physics Question on System of Particles & Rotational Motion

A solid sphere, a hollow sphere and a disc having same mass and radius roll down the same inclined plane from rest. Which one will reach the ground in least time?

A

Solid sphere

B

Hollow sphere

C

Disc

D

All will reach in same time

Answer

Solid sphere

Explanation

Solution

In rolling without slipping acceleration of all the objects down the plane is different. Acceleration of rolling body down an inclined plane
a=gsinθ1+ImR2...(i)a=\frac{g \sin \theta}{1+\frac{I}{m R^{2}}}\,\,\,...(i)
For solid sphere; I=25MR2I=\frac{2}{5} M R^{2}
IMR2=25\Rightarrow \frac{I}{M R^{2}}=\frac{2}{5}
a=gsinθ1+25=57gsinθ\therefore a=\frac{g \sin \theta}{1+\frac{2}{5}}=\frac{5}{7} g\, \sin \theta
For hollow sphere; I=25MR2I=\frac{2}{5} M R^{2}
IMR2=23\Rightarrow \frac{I}{M R^{2}}=\frac{2}{3}
a=gsinθ1+23=35gsinθ\therefore a=\frac{g \sin \theta}{1+\frac{2}{3}}=\frac{3}{5} g\, \sin \theta
For disc; I=12MR2I=\frac{1}{2} M R^{2}
IMR2=12\Rightarrow \frac{I}{M R^{2}}=\frac{1}{2}
a=gsinθ1+12=23gsinθ\therefore a=\frac{g \sin \theta}{1+\frac{1}{2}}=\frac{2}{3} g\, \sin \theta
It is obvious that acceleration of solid sphere is maximum, so solid sphere will reach the ground in least time.