Question

A solid metallic cube having total surface area 24 m2 is uniformly heated. If its temperature is increased by 10°C, calculate the increase in volume of the cube.

(Given α = 5.0 × 10–4 °C–1).

• A. 2.4 × 106 cm3
• B. 1.2 × 105 cm3
• C. 6.0 × 104 cm3
• D. 4.8 × 105 cm3

Answer 1

Answer: (A)

2.4 × 106 cm3

Answer 2

The correct option is(B): 1.2 × 105 cm3

6 × l 2 = 24

⇒ l = 2 m

$\frac{△V}{V}=3× \frac{△l}{l}$

⇒ Δ V = 3 × (αΔ T) × V

= 3 × 5 × 10–4 × 10 × (8)

= 120 × 10–3 m3

= 120 × 10–3 × 106 cm3

= 1.2 × 105 cm3