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Question

Physics Question on thermal properties of matter

A solid cylinder of radius RR made of a material of thermal conductivity K1K_1 is surrounded by a cylindrical shell of inner radius RR and outer radius 2R2R made of a material of thermal conductivity K2K_2. The two ends of the combined system are maintained at two different temperatures. Then there is no loss of heat across the cylindrical surface and the system is in steady state. The effective thermal conductivity of the system is

A

K1+K2K_1 + K_ 2

B

K1K2K1+K2\frac{K_1K_2}{K_1+K_2}

C

2K1+K24\frac{2K_1+K_2}{4}

D

K13K24\frac{K_1 3K_2}{4}

Answer

K13K24\frac{K_1 3K_2}{4}

Explanation

Solution

As there is no loss of heat, and the system is in steady state.
Qtotal =Q1+Q2\therefore \,\,Q_{\text {total }}=Q_{1}+Q_{2}
K(4R2)dθdx=K1R2dθdx+K2(3R2)dθdx\Rightarrow \frac{K\left(4 R^{2}\right) \,d \theta}{d x}=\frac{K_{1} \,R^{2} \,d \theta}{d x}+\frac{K_{2}\,\left(3 R^{2}\right)\, d \theta}{d x}
4K=K1+3K2\Rightarrow 4 K=K_{1}+3 K_{2}
K=K1+3K24\Rightarrow K=\frac{K_{1}+3 K_{2}}{4}