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Question

Physics Question on System of Particles & Rotational Motion

A solid cylinder of mass MM and radius RR rolls without slipping down an inclined plane of length LL and height hh. What is the speed of its centre of mass when the cylinder reaches its bottom -

A

2gh\sqrt{2gh}

B

34gh\sqrt{\frac{3}{4}gh}

C

43gh\sqrt{\frac{4}{3}gh}

D

4gh\sqrt{4gh}

Answer

43gh\sqrt{\frac{4}{3}gh}

Explanation

Solution

mgh=12mv2(1+K2/R2)mgh = \frac{1}{2} mv ^{2}\left(1+ K ^{2} / R ^{2}\right)
v=2gh(1+K2/R2)\Rightarrow v =\sqrt{\frac{2 gh }{\left(1+ K ^{2} / R ^{2}\right)}}