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Question

Physics Question on System of Particles & Rotational Motion

A solid cylinder of mass MM and radius RR rolls on a flat surface. Find its moment of inertia about the line of contact.

A

(32)MR2\left(\frac{3}{2}\right)MR^{2}

B

MR2MR^2

C

2MR22\,MR^2

D

(23)MR2\left(\frac{2}{3}\right)MR^{2}

Answer

(32)MR2\left(\frac{3}{2}\right)MR^{2}

Explanation

Solution

Moment of inertia of solid cylinder about OO,
ICM=12MR2I_{CM}=\frac{1}{2}MR^{2}
Moment of inertia about point of contact PP,
Ip=ICM+MR2I_{p}=I_{CM}+MR^{2} (using parallel axes theorem)
=12MR2+MR2=\frac{1}{2}MR^{2}+MR^{2}
=32MR2=\frac{3}{2}MR^{2}