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Question: A solid cylinder of mass 20 kg has length 1 m and radius 0.2 m. Then its moment of inertia (in kg-m2...

A solid cylinder of mass 20 kg has length 1 m and radius 0.2 m. Then its moment of inertia (in kg-m2) about its geometrical axis is (in kg-m2):

A

0.8

B

0.4

C

0.2

D

20.2

Answer

0.4

Explanation

Solution

The moment of inertia of cylinder about the geometrical axis

=12MR2= \frac { 1 } { 2 } M R ^ { 2 }

=20×(0.2)22=0.4 kg−m2= \frac { 20 \times ( 0.2 ) ^ { 2 } } { 2 } = 0.4 \mathrm {~kg} - \mathrm { m } ^ { 2 }