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Question

Physics Question on System of Particles & Rotational Motion

A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle inclination 30°. The centre of mass of cylinder has speed of 4 m/s. The distance travelled by the cylinder on the incline surface will be :
(Take g = 10 m/s2^2)

A

2.2 m

B

1.6 m

C

1.2 m

D

2.4 m

Answer

2.4 m

Explanation

Solution

12mv2(1+K2R2)=mgh\frac{1}{2} mv^2 ( 1 + \frac{K^2}{R^2}) = mgh
8(1+12)=10h\Rightarrow 8 ( 1 + \frac{1}{2}) = 10\,h
h=1.2mh = 1.2\,m
hl=sin30\frac{h}{l} = sin\,30^{\circ}
l=2.4ml = 2.4 \,m

So, the correct option is (D): 2.4 m