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Question: A solid conducting sphere of radius a has a net positive charge 2Q. A conducting spherical shell of ...

A solid conducting sphere of radius a has a net positive charge 2Q. A conducting spherical shell of inner radius bb and outer radius c is concentric with the solid sphere and has a net charge – Q. The surface charge density on the inner and outer surfaces of the spherical shell will be

A

2Q4πb2,Q4πc2- \frac{2Q}{4\pi b^{2}},\frac{Q}{4\pi c^{2}}

B

Q4πb2,Q4πc2- \frac{Q}{4\pi b^{2}},\frac{Q}{4\pi c^{2}}

C

0,Q4πc20,\frac{Q}{4\pi c^{2}}

D

None of the above

Answer

2Q4πb2,Q4πc2- \frac{2Q}{4\pi b^{2}},\frac{Q}{4\pi c^{2}}

Explanation

Solution

Surface charge density (σ) =ChargeSurface area= \frac{\text{Charge}}{\text{Surface area}}

So σinner=2Q4πb2\sigma_{inner} = \frac{- 2Q}{4\pi b^{2}} and σOuter=Q4πc2\sigma_{Outer} = \frac{Q}{4\pi c^{2}}