Question
Question: A solid ball of mass m is allowed to fall from a height h to a pan suspended with a spring of spring...
A solid ball of mass m is allowed to fall from a height h to a pan suspended with a spring of spring constant k. Assume the ball does not rebound and pan is massless, then amplitude of the oscillation is –
A
kmg
B
kmg + (mg2hk)1/2
C
mg 1+mg1+2hk
D
kmg [1+1+mg2hk]
Answer
\frac { \mathrm { mg } } { \mathrm { k } }$$\left\lbrack 1 + \sqrt{1 + \frac{2hk}{mg}} \right\rbrack
Explanation
Solution
mg (h + x) = 21kx2 ⇒ x2–(k2mg)x–k2mgh = 0
⇒ x = kmg + kmg (1+mg2hk)1/2