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Question: A solid ball of density r<sub>1</sub> and radius r falls vertically through a liquid of density r<su...

A solid ball of density r1 and radius r falls vertically through a liquid of density r2. Assume that the viscous force acting on the ball is F = krn, where k is a constant and n its velocity. What is the terminal velocity of the ball ?

A

4πr2(ρ1ρ2)3k\frac{4\pi r^{2}(\rho_{1}–\rho_{2})}{3k}

B
C

2πg(ρ1+ρ2)3gr2k\frac{2\pi g(\rho_{1} + \rho_{2})}{3gr^{2}k}

D

None of these

Answer

4πr2(ρ1ρ2)3k\frac{4\pi r^{2}(\rho_{1}–\rho_{2})}{3k}

Explanation

Solution

Net force on the ball = 0

(when terminal velocity is attained).

Hence,

Weight = upthrust + viscous force

\ 43\frac{4}{3} pr3 r1g = 43\frac{4}{3} pr3r2g + krnT

\ nT = 4πgr23k\frac{4\pi gr^{2}}{3k} (r1 – r2)