Question

A solenoid of cross-sectional area 2 x 10~4 m2 and 900 turns has 0.6 A m2 magnetic moment. Then the current flowing through it is

• A. 2.24 A
• B. 2.34 m A
• C. 3.33 A
• D. 3.33 Ma

Answer 1

Answer: (C)

3.33 A

Answer 2

: Here, n = 900 turns,

$\mathrm { A } = 2 \times 10 ^ { - 4 } \mathrm {~m} ^ { 2 } , \mathrm {~m} _ { \mathrm { s } } = 0.6 \mathrm { Am } ^ { 2 }$

The magnetic moment of solenoid,

The current flowing through the solenoid is,

$\mathrm { I } = \frac { \mathrm { m } _ { \mathrm { s } } } { \mathrm { NA } } = \frac { 0.6 } { 900 \times 2 \times 10 ^ { - 4 } } = 3.33 \mathrm {~A}$