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Question: A solenoid is 1.0 metre long and it has 4250 turns. If a current of 5.0 ampere is flowing through it...

A solenoid is 1.0 metre long and it has 4250 turns. If a current of 5.0 ampere is flowing through it, what is the magnetic field at its centre [μ0=4π×10−7\left[ \mu _ { 0 } = 4 \pi \times 10 ^ { - 7 } \right. weber // amp −m]\left. - m \right]

A

5.4×10−25.4 \times 10 ^ { - 2 } weber /m2/ \mathrm { m } ^ { 2 }

B

C

1.35×10−21.35 \times 10 ^ { - 2 } weber /m2/ \mathrm { m } ^ { 2 }

D

0.675×10−20.675 \times 10 ^ { - 2 } weber /m2/ \mathrm { m } ^ { 2 }

Answer

Explanation

Solution

Magnetic field at the centre of solenoid

(B)=μ0ni( B ) = \mu _ { 0 } n i

Where n = Number of turns /meter

∴B=4π×10−7×4250×5=2.7×10−2 Wb/m2\therefore B = 4 \pi \times 10 ^ { - 7 } \times 4250 \times 5 = 2.7 \times 10 ^ { - 2 } \mathrm {~Wb} / \mathrm { m } ^ { 2 }