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Question: A solenoid has a core of a material with relative permeability of 500. The windings of the solenoid ...

A solenoid has a core of a material with relative permeability of 500. The windings of the solenoid are insulated from the core and carry a current of 2 A. If the number of turns is 1000 per meter, then magnetisation is

A

7.78 x 105 A m-1

B

8.88xl05Am-1

C

9.98 x 105 A m-1

D

10.2 x 10s A m-1

Answer

9.98 x 105 A m-1

Explanation

Solution

: As B=μ0(M+H)\mathrm { B } = \mu _ { 0 } ( \mathrm { M } + \mathrm { H } )

Magnetization,

then ,

M=μ0μrHμ0Hμ0=(μr1)H(B=μ0μrH)\mathrm { M } = \frac { \mu _ { 0 } \mu _ { \mathrm { r } } \mathrm { H } - \mu _ { 0 } \mathrm { H } } { \mu _ { 0 } } = \left( \mu _ { \mathrm { r } } - 1 \right) \mathrm { H } \left( \because \mathrm { B } = \mu _ { 0 } \mu _ { \mathrm { r } } \mathrm { H } \right)

Here, and

or M=9.98×105Am1\mathrm { M } = 9.98 \times 10 ^ { 5 } \mathrm { Am } ^ { - 1 } .