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Question

Physics Question on Inductance

A solenoid has 20002000 turns wound over a length of 0.30m0.30\, m . The area of its cross-section is 1.2?103m21.2 ? 10^{-3}\, m^2. Around its central section, a coil of 300300 turn is wound. If an initial current of 2A2A in the solenoid is reversed in 0.25s0.25\, s, then the emf induced in the coil is

A

6?104V6 ? 10^{-4}\, V

B

4.8?103V4.8 ? 10^{-3}\, V

C

6?102V6 ? 10^{-2}\, V

D

48mV48\,mV

Answer

48mV48\,mV

Explanation

Solution

Induced emf e=Mdidte=M \frac{di}{dt}
=μ0N1N2Al.didt=\frac{\mu_{0}\,N_{1}\,N_{2}\,A}{l}. \frac{di}{dt}
=4π×107×2000×300×1.2×1030.30=\frac{4\pi\times10^{-7}\times2000\times300\times1.2\times10^{-3}}{0.30}
×2(2)0.25\times\frac{\left|2-\left(-2\right)\right|}{0.25}
=48.2×103V=48mV=48.2\times10^{-3}\,V=48\,mV