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Question

Physics Question on Magnetic Field

A solenoid 1.5m1.5\, m long and 0.4cm0.4\, cm in diameter possesses 1010 turns per cm length. A current of 5A5\, A flows through it. The magnetic field at the axis inside the solenoid is

A

2π×103T2\pi \times10 ^{-3}T

B

2π×105T2\pi \times 10 ^{-5}T

C

4π×102T4\pi \times 10 ^{-2}T

D

4π×103T4\pi \times 10 ^{-3}T

Answer

2π×103T2\pi \times10 ^{-3}T

Explanation

Solution

Magnetic field at the axis inside the solenoid B=μ0niB = \mu_{0}\, ni Here, n=10n = 10 tums/cm =10001000 turns/m, i=5Ai = 5\, A B=4π×107×1000×5B = 4\pi \times10^{-7} \times1000 \times5 =2π×103T = 2\pi \times10 ^{-3} \, T